Given a list lst and a number N, create a new list that contains each number in lst at most N times without reordering.

For example if N = 2, and the input is [1,2,3,1,2,1,2,3], you take [1,2,3,1,2], skip the next 1 and 2 because this would lead to those numbers being in the result more than N times. Finally, take 3, which leads to [1,2,3,1,2,3].

deleteNth([1,1,1,1],2) // return [1,1]

deleteNth([20,37,20,21],1) // return [20,37,21]

Tests

deleteNth([20,37,20,21], 1)
deleteNth([1,1,3,3,7,2,2,2,2], 3)

Good luck!

This challenge comes from JustyFY on CodeWars. Thank you to CodeWars, who has licensed redistribution of this challenge under the 2-Clause BSD License!

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